The sum of first n terms of an AP is (4n2 + 2n). The nth term of this AP is

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Mathematics Foundation

Sum of n terms of an AP

Question

The sum of first n terms of an AP is (4n² + 2n). The nth term of this AP is

(7n – 3)

(8n – 2)

(8n + 2)

(6n – 2)

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T_n = (S_n – S_{n – 1}) = (4n² + 2n) – [4(n – 1)²] + 2(n – 1)

= (4n² + 2n) – (4n² – 6n + 2) = (8n – 2).