Engineering
Physics
Angular Momentum and Conservation of Angular Momentum
Question

The time dependence of the position of a particle of mass m = 2kg is given by r→(t)=2t i^−3t2 j^ . Its angular momentum, with respect to the origin, at time t = 2 is :

36  k^

−48  k^

−34  (k^−i^)

48 (i^+j^)

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Solution

At t = 2

v→=2i^−12j^

P→=mv→=4i^−24j^

At t = 2

r→=4i^−24j^

L→=r→×P→=|i^j^k^4−1204−240|

={4(−24)+4×12}k^

=(−96+48)k^

=(−)48k^