Engineering
Physics
Spectrum of Hydrogen and Hydrogen Like Atoms
Question

The time period of revolution of electron in its ground state orbit in a hydrogen atom is 1.6 × 10–16 s. The frequency of revolution of the electron in its first excited state (in s–1) is :

1.6 × 1014

5.6 × 1012

7.8 × 1014

6.2 × 1015

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Solution

T∝rv∝n2z×nz∝n3z2

T1T2=n13n23=18

T2 = 8T1

= 8 × 1.6 × 10–16 = 12.8 × 10–16

f2=112.8×10−16≈7.8×1014