The uniform chain shown is hanging from a ceiling, then =

Engineering

Physics

Equilibrium

Chain and Rope System

Free Body Diagram

Question

The uniform chain shown is hanging from a ceiling, then $\frac{AB}{BC}$ =

$\frac{9}{16}$

$\frac{7}{9}$

$\frac{16}{9}$

$\frac{3}{4}$

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$\frac{T_{Y}}{T_{X}} = \frac{W_{AC}}{T_{X}} = \tan 53 º$ .....(1)

$\frac{T_{Y}^{'}}{T_{X}} = \frac{W_{BC}}{T_{X}} = \tan 37 º$ .....(2)

$∴ \frac{W_{AC}}{W_{BC}} = \frac{λ (AC)}{λ (BC)} = \frac{16}{9}$

$∴ \frac{AC}{BC} = \frac{16}{9} \Rightarrow \frac{AB}{BC} = \frac{7}{9}$