Engineering
Mathematics
Introduction to Determinants
Question

The value of | U | equals 

0
1
2

– 1

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Solution
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An – An–2 = A2 – I  ⇒  A50 = A48 + A2 – I
Further,
A48 = A46 + A2 – I
A46 = A44 + A2 – I
A4 = A2 + A2 – I
________________
A50 = 25A2 – 24I
Here,
A2=[100101010][100101010]=[100110101]
A50=[25002525025025]24[100010001]=[10025102501]
∴  |A50| = 1
Also tr(A50) = 1 + 1 + 1 = 3 further,
[10025102501][xyz]=[12525][xyz]2=[100] similarly
2=[010] and 3=[001][100010001], i.e. |U| = 1
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