Engineering
Mathematics
Introduction to Functions
Modulus Function
Introduction to Definite Integral
Question

The value of the integral I=∫−22 sin2⁡xdxxπ+12(where [x] denotes the greatest integer less than or equal to x) is:

4 – sin 4

0

sin 4

4

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Solution

I =∫−22sin2x dx[xπ]+12

I=∫−22sin2x dx −[xπ]−12 ⇒2I = 0⇒I = 0