The value of 'x', if hydrated salt Na2CO3.xH2O undergo 63% loss in mass on heating and becomes anhydrous, is

Engineering

Chemistry

Estimation Percentage of Element

Question

The value of 'x', if hydrated salt Na₂CO₃.xH₂O undergo 63% loss in mass on heating and becomes anhydrous, is

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Na₂CO₃.xH₂O (s) → Na₂CO₃(s) + xH₂O (g)
Let 100 g of Na₂CO₃.xH₂O be present
$∴ \frac{100 x}{106 + 18 x}$ mol of H₂O formed
$∴ 63 = \frac{100 x}{106 + 18 x}$ = (18)
6678 + 1134 = 1800 x
666x = 6678
x = 10.027