The value of ∫ln 2ln 3x sinx2sinx2+sin (ln 6−x2) dx is :
ln 32
12ln 32
14ln 32
16ln 32
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Let x2=t xdx=dt2
I=12∫ℓn2ℓn3sintsint+sin(ℓn6−t)dt ...............(1)
I=12∫ℓn2ℓn3sin(ℓn6−t)sint+sin(ℓn6−t)dt ...............(2)
Add (1) & (2)
2I=12∫ℓn2ℓn3dt
I=14(ℓn3−ℓn2)=14ℓn32