The volume (in mL) of 0.5 M NaOH required for the complete reaction with 150 mL of 1.5M H3PO3 solution is

Engineering

Chemistry

Solution Stoichiometry

Question

The volume (in mL) of 0.5 M NaOH required for the complete reaction with 150 mL of 1.5M H₃PO₃ solution is

900

1150

1250

1350

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

1.5 M H₃PO₄ 150 mL
H₃PO₃ + 2NaOH → Na₂HPO₃ + 2H₂O
0.225 450
$M = \frac{n_{NaOH}}{V (l)} \Rightarrow V = \frac{450}{0 .5} = 900 mL$