The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561Å. The wavelength of the second spectral line in the Balmer series of singly-ionized helium atom is

Engineering

Physics

Bohrs Model of Atom

Question

4687 Å

1215 Å

2430 Å

1640 Å

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$\frac{hc}{6561} = 13 .6 [\frac{1}{2^{2}} - \frac{1}{3^{2}}]$

$\frac{hc}{λ} = 13 .6 \times 4 [\frac{1}{2^{2}} - \frac{1}{4^{2}}]$

$\frac{hc}{6561} = 13 .6 \times \frac{5}{36}$

$\frac{hc}{λ} = 13 .6 \times 4 \times \frac{3}{16}$

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