There are 3 red, 3 white and 3 green balls in a bag. One ball is drawn at random from a bag:
P is the event that ball is red.
Q is the event that ball is not green.
R is the event that ball is red or white.
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There are 3 red balls, 3 white balls and 3 green balls.
Thus, total number of balls = 9, n(S) = 9
P, the ball is red, n(R) = 3
Q, the ball is not green, n(Q) = 9 − 3 = 6
R, the ball is red or white, n(R) = 3 + 3 = 6