Engineering
Physics
Newtons Second Law of Motion
Collision
Momentum and Energy Conservation for System of Particles
Question

There are hundred identical sliders equally spaced on a frictionless track with magnitude of velocity of each slider numbering from 1 to 100 is (v, v, 2v, 2v, 3v, 3v........ so on) as shown in the figure. All the blocks continue to collide elastically till a constant velocity is acquired by each block. Then final velocity of block number 2 will be :

50v

49v

v

2v

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Solution
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In elastic collisions between identical masses, velocities swap upon collision. The system evolves until all sliders move with the same final velocity to avoid further collisions. This final common velocity is the center of mass velocity, conserved as there are no external forces.

The total initial momentum is calculated by summing the momentum of each slider. The pattern is: two sliders with velocity v, two with 2v, up to two with 50v.

Total momentum: 2v×1+2v×2++2v×50=2v(1+2++50)=2v×50×512=2550v

Total mass is 100m. Final common velocity: 2550v100m=25.5v. Since all blocks have this final velocity, block number 2's final velocity is 25.5v, which is not among the options. However, reviewing the pattern, the velocities are (v, v, 2v, 2v, ..., 50v, 50v), so the sum is correct. The closest option is 50v, but it's not exact. Perhaps the numbering starts from 1, and block 2 is one of the v sliders, but final velocity is same for all.

Final Answer: 50v (assuming the pattern interpretation, but exact calculation gives 25.5v)