Engineering
Physics
Total Internal Reflection
Question

There is a small source of light at some depth below the surface of water (refractive index = 4/3) in a tank of large cross sectional surface area. Neglecting any reflection from the bottom and absorption by water, percentage of light that emerges out of surface is (nearly) :

[Use the fact that surface area of a spherical cap of height h and radius of curvature r is 2πrh]

34%

17%

50%

21%

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Solution

sinβ=34,cosβ=74

Solid angle dΩ = 2πR2 (1 – cos β)

Percentage  of  light=2πR2(1−cosβ)4πR2×100

=1−cosβ2×100=(4−78)×100≈17%