From graph, slope = –1

∴ eq = log₁₀V + log₁₀T = constant

∴ VT = constant or PV² = constant

$\mathrm{C}={\mathrm{C}}_{\mathrm{v}}+\frac{\mathrm{R}}{1-\mathrm{n}}\therefore \mathrm{C}=\frac{5\mathrm{R}}{2}+\frac{\mathrm{R}}{1-2}=\frac{3\mathrm{R}}{2}$

$\therefore \mathrm{q}=\mathrm{nC\Delta T}=3\times \frac{3\mathrm{R}}{2}\times (1000-100)=4050\mathrm{R}$

$\mathrm{\Delta U}=\mathrm{nCv\Delta T}=3\times \frac{5\mathrm{R}}{2}\times (1000-100)=6750\mathrm{R}$

∴ W = ΔU – q = 6750 R – 4050 R = 2700 R