Three point particles of masses 1.0 kg, 1.5 kg and 2.5 kg are placed at three corners of a right angle triangle of sides 4.0 cm, 3.0 cm and 5.0 cm as shown in the figure. The center of mass of the system is at a point :

Engineering

Physics

Center of Mass

Question

1.5 cm right and 1.2 cm above 1kg mass

0.6 cm right and 2.0 cm above 1kg mass

2.0 cm right and 0.9 cm above 1 kg mass

0.9 cm right and 2.0 cm above 1kg mass

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Take 1kg mass at origin

$X_{cm} = \frac{1 \times 0 + 1 .5 \times 3 + 2 .5 \times 0}{5} = 0 .9 cm$

$Y_{cm} = \frac{1 \times 0 + 1 .5 \times 0 + 2 .5 \times 4}{5} = 2 cm$