Three unbiased coins are tossed, what is probability of getting exactly two heads ?

Engineering

Mathematics

Basic Definitions Related to Probability

Question

Three unbiased coins are tossed, what is probability of getting exactly two heads ?

A

$\frac{1}{3}$

B

$\frac{3}{4}$

C

$\frac{2}{3}$

D

$\frac{3}{8}$

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Possible outcomes of tossing three coins are :

(HHH), (HHT), (HTH), (THH), (TTT), (TTH), (THT), (HTT)
here H and T are denoted for Head and Tail.
Total no. of outcomes = 8
no. of outcomes with exactly two heads = 3

∴ required probability $= \frac{3}{8}$

∴ Option D is correct.