To get output '1' at R, for the given logic gate circuit the input values must be:

Engineering

Physics

Logic Gates New

Question

X = 0, Y = 0

X = 1, Y = 1

X = 1, Y = 0

X = 0, Y = 1

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$R = \bar{P + Q} = \bar{(\bar{x} + y) + (\bar{x \bar{y}})}$

$= (\bar{\bar{x} + y}) \cdot (x \bar{y})$

$= (x \cdot \bar{y}) \cdot (x \bar{y})$

$= x \bar{y}$