Two balls of masses 2kg and 3kg slide along a frictionless horizontal surface with speeds of 4 m/s and 2m/s, respectively. After an inelastic collision, the balls stick together and move at a speed of 2m/s. What direction did the two balls move before the collision?

Engineering

Physics

Collision

Momentum and Energy Conservation for System of Particles

Summation of Vectors

Question

Two balls of masses 2kg and 3kg slide along a frictionless horizontal surface with speeds of 4 m/s and 2m/s, respectively. After an inelastic collision, the balls stick together and move at a speed of 2m/s. What direction did the two balls move before the collision?

In opposite directions

In the same direction

The situation described is impossible

At an angle not equal to 0° or 180°

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$\begin{matrix} m_{1} = 2 \\ m_{2} = 3 \end{matrix} \begin{matrix} v_{1} = 4 \\ v_{2} = 2 \end{matrix}] v = 2$

m₁v₁ = 8 m₂v₂ = 6
p_f = (m₁ + m₂)v = (2 + 3)² = 10

${\vec{p}}_{1} + {\vec{p}}_{2} = {\vec{p}}_{f}$

$8 \hat{i} + 6 \hat{j} = {\vec{p}}_{f} | {\vec{p}}_{f} | = 10$ .