Two batteries with e.m.f. 12 V and 13 V are connected in parallel across a load resistor of 10 Ω. The internal resistances of the two batteries are 1 Ω and 2 Ω respectively. The voltage across the load lies between:

Engineering

Physics

Combination of Cells and Batteries

Question

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$v = i (10) = \frac{ε_{eq}}{R_{eq}} (10)$

$v = \frac{\frac{\frac{12}{1} + \frac{13}{2}}{\frac{1}{1} + \frac{1}{2}}}{10 + \frac{2}{3}} \times 10 = 11 .56 volts$