Two bodies of masses m and 4m are placed at a distance r. The gravitational potential at a point on the line joining them where the gravitational field is zero is :

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Physics

Physical Quantities

Question

$- \frac{9 Gm}{r}$

$- \frac{6 Gm}{r}$

$- \frac{9 Gm}{r}$

zero

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$\frac{Gm}{x^{2}} = \frac{G (4 m)}{{(r - x)}^{2}}$

$\frac{1}{x} = \frac{2}{r - x}$

r – x = 2x

$3 x = \frac{r}{3}$

$x = \frac{r}{3}$

$- \frac{Gm}{r / 3} - \frac{G (4 m)}{2 r / 3}$

$- \frac{3 Gm}{r} - \frac{6 Gm}{r} = \frac{9 Gm}{r}$

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