Engineering
Physics
Physical Quantities
Question

Two capacitors C1 and C2 are charged to 120V and 200V respectively. It is found that by connecting them together the potential on each one can be made zero. Then

3C1 = 5C2

9C1 = 4C2

5C1 = 3C2

3C1 + 5C2 = 0

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Solution
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C1 × 120 = C2  × 200

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