Two charges, each equal to q, are kept at x = –a and x = a on the x-axis. A particle of mass m and charge is placed at the origin. If charge q0 is given a small displacement (y << a) along the y-axis, the net force acting on the particle is proportional to :

Engineering

Physics

Charge and Coulombs Law

Question

Two charges, each equal to q, are kept at x = –a and x = a on the x-axis. A particle of mass m and charge $q_{0} = \frac{q}{2}$ is placed at the origin. If charge q₀ is given a small displacement (y << a) along the y-axis, the net force acting on the particle is proportional to :

–y

$- \frac{1}{y}$

$\frac{1}{y}$

LiveFree JEE Main Previous Year Online Papers Live Free JEE Advance Previous Year Online Papers

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

F = 2F₁ cos $θ$

$= \frac{2 \times {kq}_{0} q}{{(y^{2} + a^{2})}^{3 / 2}} y$

$\Rightarrow$ F $\propto$ y