Two coins are tossed once. Find P(A / B) in given cases:A = No tail appears, B = No head appears.

Engineering

Mathematics

Conditional Probability

Question

Two coins are tossed once. Find P(A / B) in given cases:
A = No tail appears, B = No head appears.

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We have,A = {HH}, B = {TT}

∴ P(A∩B) = 0 and P(B) = 1

∴

P (A / B) = \frac{P (A \cap B)}{P (B)} = \frac{0}{1}

∴ P(A/B) = 0

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