Two equal resistances when connected in series to a battery, consume electric power of 60 W. If these resistances are now connected in parallel combination to the same battery, the electric power consumed will be:

Engineering

Physics

Mechanical Power

Question

30 W

60 W

240 W

120 W

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Assuming constant voltage supply

$P = 60 = \frac{V^{2}}{R_{1} + R_{2}} (1)$

$AndP' = \frac{V^{2}}{R_{1}} + \frac{V^{2}}{R_{2}} = \frac{2 V^{2}}{R_{1}} = 4 P = 4 \times 60$

= 240 W