Engineering
Physics
Radiation
Question
Two identical beakers A and B contain equal volumes of two different liquids at 60º C each and left to cool down. Liquid in A has density 8 × 102 kg/m3 and specific heat of 2000 J kg–1 K–1 while liquid in B has density of 103 kg m–3 and specific heat of 4000 J kg–1 K–1. Which of the following best describes their temperature versus time graph schematically? (assume the emissivity of both the beakers to be the same)
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Solution
T = T0 + (Ti – T0)e-kt
ρASA = 2000 × 8 × 102 = 16 × 105
ρBSB = 4000 × 103 = 4 × 106
ρASA < ρBSB