Engineering
Physics
Basics of Simple Harmonic Motion
Question

Two independent harmonic oscillators of equal mass are oscillating about the origin with angular frequencies ω1 and ω2 and have total energies E1 and E2, respectively. The variations of their momenta p with position x are shown in the figures. If ab=n2 and aR=n, then the correct equation(s) is (are) :

 E1ω1=E2ω2

 ω2ω1=n2

E1ω1 = E2ω2

ω1ω2 = n2

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Solution

 

x = a; P = 0; x = 0; P = b

b = Maω1                      .....(i)          ⇒    for 1st particle

 E1=b22m

R = mRω2                     ......(ii)        ⇒    for 2nd particle

 E2=R22m=ab2m

 E1E2=ba=1n2=ω1ω2

 2=1;1=ba

(from (i) & (ii) equations)

 ω1ω2=ba=1n2

⇒  R2 = ab