Two large vertical and parallel metal plates having a separation of 1 cm are connected to a DC voltage source of potential difference X. A proton is released at rest midway between the two plates. It is found to move at 45° to the vertical JUST after release. Then X is nearly

Engineering

Physics

Physical Quantities

Question

1 × 10^–9 V

1 × 10^–10 V

1 × 10^–5 V

1 × 10^–7 V

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$\frac{qV}{d} = mg$

$V = \frac{mgd}{q} = \frac{1 .6 \times 10^{- 27} \times 10 \times 10^{- 2}}{1 .6 \times 10^{- 19}}$

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