Two particles A and B having equal mass are interconnected by a light inextensible string that passes over a smooth pulley. One of the mass is pulled downward by a constant force 'F' as shown in diagram, then the acceleration of the centre of mass of the system (A + B) is :

Engineering

Physics

Newtons Second Law of Motion

Constrained Relation

Center of Mass

Question

Two particles A and B having equal mass are interconnected by a light inextensible string that passes over a smooth pulley. One of the mass is pulled downward by a constant force 'F' as shown in diagram, then the acceleration of the centre of mass of the system (A + B) is :

zero

$\frac{F}{2 M}$ upwards

$\frac{F}{M}$ downwards

$\frac{F}{2 M}$ downwards

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$a_{c} = \frac{Ma - Ma}{2 M} = 0$ .