Two particles of equal mass have initial velocities \left(\overset{\rightarrow}{v}\right)_{1} = 2 \hat{i} m / s \& \left(\overset{\rightarrow}{v}\right)_{2} = 2 \hat{j} m / s. First particle has an acceleration \left(\overset{\rightarrow}{a}\right)_{1} = \textrm{ } \left(\right. 3 \hat{i} \textrm{ } + \textrm{ } 3 \hat{j} \left.\right) \textrm{ }\textrm{ } m / s^{2} while the acceleration of the other particle is \overset{\rightarrow}{0}. The centre of mass of the two particles move in a

Engineering

Physics

Straight Line Motion

Newtons Second Law of Motion

Center of Mass

Question

Two particles of equal mass have initial velocities ${\vec{v}}_{1} = 2 \hat{i} m / s & {\vec{v}}_{2} = 2 \hat{j} m / s$ . First particle has an acceleration ${\vec{a}}_{1} = (3 \hat{i} + 3 \hat{j}) m / s^{2}$ while the acceleration of the other particle is $\vec{0}$ . The centre of mass of the two particles move in a

parabola

straight line

circle

ellipse

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${\vec{a}}_{cm} = \frac{3 \hat{i} + 3 \hat{j}}{2} {\vec{v}}_{cm} = \hat{i} + \hat{j}$

${\vec{v}}_{cm} | | {\vec{a}}_{cm}$ .