Two sheets of thickness d and 2 d and same area are touching each other on their face. Temperature TA, TB, TC shown are in geometric progression with common ratio r = 2. Then ratio of thermal conductivity of thinner and thicker sheet are

Engineering

Physics

Conduction of Heat

Question

Two sheets of thickness d and 2 d and same area are touching each other on their face. Temperature T_A, T_B, T_C shown are in geometric progression with common ratio r = 2. Then ratio of thermal conductivity of thinner and thicker sheet are

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T_A = θ

T_B = 2θ

T_C = 4θ

$\frac{2 θ - θ}{(\frac{1}{K_{1}} \frac{d}{A})} = \frac{4 θ - 2 θ}{[\frac{1}{K_{2}} \frac{2 d}{A}]}$

solving above we get K₁ = K₂