Two solid objects of the same mass are supplied with heat at the same rate Q/t. The temperature of the first object with latent heat L1 and specific heat capacity c1 changes according to graph 1 on the diagram. The temperature of the second object with latent heat L2 and specific heat capacity c2 changes according to graph 2 on the diagram. Based on what is shown on the graph, the latent heats L1 and L2 and the specific heat capacities c1 and c2 in solid state obey which of the following relationships:

Engineering

Physics

Calorimetry

Question

Two solid objects of the same mass are supplied with heat at the same rate $∆$ Q/ $∆$ t. The temperature of the first object with latent heat L₁ and specific heat capacity c₁ changes according to graph 1 on the diagram. The temperature of the second object with latent heat L₂ and specific heat capacity c₂ changes according to graph 2 on the diagram.

Based on what is shown on the graph, the latent heats L₁ and L₂ and the specific heat capacities c₁ and c₂ in solid state obey which of the following relationships:

L₁ < L₂ ; c₁ > c₂

L₂ < L₁ ; c₁ > c₂

L₁ < L₂ ; c₁ < c₂

L₂ < L₁ ; c₂ > c₁

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L₂ > L₁ [ $∵$ Change in state takes more time for 2]
c₁ < c₂ [ $∵$ Final temperature of 1 is more for solid state]
Alternative :-
According to the calorimetric relation $\frac{Δθ}{Δt} = mc \frac{ΔT}{Δt} ΔT = ((\frac{Δθ}{Δt}) \frac{1}{mc}) Δt$
Slope of TVs t graph will be $\propto \frac{1}{c}$
For 1st solid slope is more initially. So it's c will be lesser i,e.

$C_{1} < C_{2}$
For the curve parallel to time axis $\frac{Δθ}{Δt} = m \frac{L_{1}}{t_{1}} = m \frac{L_{2}}{t_{2}}$