Two solid spheres of same radius (R) and of same material are placed in such a way that their centres are 2R apart. The gravitational force between them is directly proportional to :

Foundation

Physics Foundation

Gravitation

Question

R⁴

R^–4

R²

R^–2

LiveFree JEE Main Previous Year Online Papers Live Free JEE Advance Previous Year Online Papers

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

Let the density of sphere is r.
   Gravitational force between
   speres :
$F = \frac{GMM}{(2 R)^{2}}$
$Mass: density \times volume = ρ \times \frac{4}{3} {πR}^{3}$
$\frac{G (4 / 3 {πR}^{3} ρ) (4 / 3 {πR}^{3} ρ)}{(2 R)^{2}}$
$F \propto \frac{R^{6}}{R^{2}} or F \propto R^{4}$

Please subscribe our Youtube channel to unlock this solution.