Two solutions, A and B, each of 100 L was made by dissolving 4g of NaOH and 9.8 g of H2SO4 in water, respectively. The pH of the resultant solution obtained from mixing 40 L of solution A and 10 L of solution B is_______

Engineering

Chemistry

pH Calculation for Acids and Bases

Question

Two solutions, A and B, each of 100 L was made by dissolving 4g of NaOH and 9.8 g of H₂SO₄ in water, respectively. The pH of the resultant solution obtained from mixing 40 L of solution A and 10 L of solution B is________.

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$M_{H_{2} {SO}_{4}} \Rightarrow \frac{9 .8}{98 \times 100} = 10^{- 3}$

$M_{NaOH} \Rightarrow \frac{4}{40 \times 100} = 10^{- 3}$

$= \frac{40 \times 10^{- 3} - 10 \times 10^{- 3} \times 2}{50} = \frac{20}{50} \times 10^{- 3}$

$[{OH}^{-}] = \frac{2}{5} \times 10^{- 3}$

pOH = 3.397

pH = 10.603