is equal to:

Engineering

Mathematics

Trigonometric Limits

Question

$\underset{x \to 0}{Lim} \frac{xcot (4 x)}{\sin^{2} {xcot}^{2} (2 x)}$ is equal to:

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$\underset{x \to 0}{Lim} \frac{xcot 4 x}{\sin^{2} {xcot}^{2} 2 x} = \underset{x \to 0}{Lim} (\frac{x}{\tan 4 x}) {(\frac{\tan 2 x}{sinx})}^{2} = \frac{1}{4} \times 4 = 1$