Engineering
Mathematics
One to The Power Infinity Form
Question

limx→0(3x2+27x2+2)1x2 is equal to :

e2

1e

1e2

e

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Solution

Let L=limx→0(3x2+27x2+2)1x2=elimx→01x2{3x2+27x2+2−1}=elimx→01x2{−4x27x2+2}=e−42=e−2