Engineering
Mathematics
Multiplication of Matrices
Symmetric and Skew Symmetric Matrices
Question

Using elementary row transformations, find the inverse of the following matrix:
2345

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Solution
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Let A=2345

 we can write, A IA       where I is che xaidontity 

                      ⇒ – 1A A1IA.

                      ⇒ I A1A.       (we use this idea to get  our answer) 

2    34    5=1    00    1A

applying R1R12, we get

13/245=1/2001A

applying R2 → R2 – 4R1, we get

13/2011=1/2021A

applying R2R211, we get

13/201=1/20211111A

applying R1R1+32R2 , we get

1    00    1=511322211111A.

Thus, A1=511322211111

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