Engineering
Mathematics
Algebra of Matrices
Inverse of a Matrix
Question

Using elementary tansormations, find the inverse of each of the matrices, if it exists in [2111]

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Solution
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A=[2111]

|A| = 2 – 1 = 1 ≠ 0
Hence, A–1 exists.
Now, A = lA
[2111]=[1001]A
[1011]=[1101]A               (R1 → R1 – R2)
[1001]=[1112]A            (R2 → R2 – R1)
Hence, A1=[1112]