Engineering
Mathematics
Algebra of Matrices
Inverse of a Matrix
Question

Using elementary transformations, find the inverse of each of the matrices, 
3142

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Solution
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A = IA [ row transformation ] 
[31024=7]=[1001]A

R1 ↔ 1/3R1
 [110/327]=[1/3001]A
R2 → R2 – 2R1

[110/301/3]=[1/302/31]A

R2 → 3R2

[110/301]=[1/3023]A

R1 → R1 – 10 / 3R2

[1001]=[71023]A

 A1=[71023]