Water enters a horizontal pipe of non- uniform cross-section with a velocity of 0.5 m/s and leaves the other end with a velocity of 0.7 m/s. The pressure of water at the first end is 103 N/m2. Calculate pressure at the other end. (Density of water = 1.0 × 103 kg/m3)

Engineering

Physics

BernoulIis Equation and Equation of Continuity

Question

Water enters a horizontal pipe of non- uniform cross-section with a velocity of 0.5 m/s and leaves the other end with a velocity of 0.7 m/s. The pressure of water at the first end is 10³ N/m². Calculate pressure at the other end. (Density of water = 1.0 × 10³ kg/m³)

980 N/m²

880 N/m²

None of these

800 N/m

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$\frac{10^{3}}{10^{4}}$ + $\frac{0 {.5}^{2}}{2 \times 10}$ = $\frac{p}{10^{4}}$ + $\frac{0 {.7}^{2}}{2 \times 10}$
$\frac{p}{10^{4}}$ = $\frac{1}{10}$ + = $\frac{0.88}{10}$