What is the position and nature of image formed by lens combination shown in figure? (f1, f2 are focal lengths)

Engineering

Physics

Plane Mirror New

Question

What is the position and nature of image formed by lens combination shown in figure? (f₁, f₂ are focal lengths)

70 cm from point B at right; real

40 cm from point B at right; real

70 cm from point B at left; virtual

$\frac{20}{3} cm$ from point B at right, real

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image by convex lens:

$\frac{15}{v} - \frac{1}{u} = \frac{1}{f}; \frac{1}{v} + \frac{1}{20} = \frac{1}{5}$

$v = \frac{20}{3} cm$

Image by concave lens:

$u = [\frac{20}{3} - 2] = \frac{14}{3} cm$

$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}; \frac{1}{v} - \frac{3}{14} = - \frac{1}{5}$

v = 70 cm