What is the weight of solute present in 2 L of 0.6 M Na2CO3 ?
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Molarity of Na2CO3 = 2 moles/litre
So 1L of Na2CO3 contains = 0.6 moles
2L of Na2CO3 will contain = 2 × 0.6 = 1.2 moles
Now, Molecular wt. of Na2CO3 = 106 g
∵ 1 mole of Na2CO3 has weight = 106 g
∴ 1.2 mole of Na2CO3 will have weight
= 106 × 1.2 = 127.2 g