What volumes should you mix of 0.2 M NaCl and 0.1 M CaCl2 solution so that in resulting solution the concentration of positive ion is 40% lesser than concentration of negative ion. Assuming total volume of solution 1000 mL.

Engineering

Chemistry

Dilution and Mixing of Solution

Solution Stoichiometry

Question

What volumes should you mix of 0.2 M NaCl and 0.1 M CaCl₂ solution so that in resulting solution the concentration of positive ion is 40% lesser than concentration of negative ion. Assuming total volume of solution 1000 mL.

600 mL NaCl, 400 mL CaCl₂

800 mL NaCl, 200 mL CaCl₂

400 mL NaCl , 600 mL CaCl₂

None of these

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V₁ , NaCl → Na+ + Cl^–
0.2 V₁ 0.2 V₁ 0.2 V₁

V₂       ,   CaCl₂ →    Ca²⁺   +    2Cl^–
               0.1 V₂       0.1 V₂       2 × 0.1 V₂
$∴$ [+ve] = 0.6 [–ve]
$(\frac{0 .2 V_{1} + 0 .1 V_{2}}{V_{1} + V_{2}}) = 0 .6 (\frac{0 .2 V_{1} + 0 .1 V_{2}}{V_{1} + V_{2}})$
   = 0.12 V₁ + 0.12 V₂
   0.08 V₁ = 0.02 V₂