Engineering
Physics
Ohm Law and Current Basics
Question

When 5V potential difference is applied across a wire of length 0.1 m, the drift speed of electron is 2.5 × 10–4 ms–1. If the electron density in the wire is 8 × 1028 m–3, the resistivity of the material is close to

1.6 × 10–7 Ω-cm

1.6 × 10–6 Ω-cm

1.6 × 10–8 Ω-cm

1.6 × 10–5 Ω-cm

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Solution

V=neAvdρA

ρ=vnevd

=58×1028×1.6×1019×2.5×104×0.1

=532×104= 0.156 × 104= 1.6 × 105