When tossing a fair 6-sided die, the probability of not getting 3 would be

Engineering

Mathematics

Conditional Probability

Question

$\frac{5}{7}$

$\frac{1}{6}$

$\frac{5}{6}$

$\frac{2}{6}$

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Complement : P( $A$ ) = 1 – P(A)

3

) = 1 – P(3) =

1 - \frac{1}{6} = \frac{5}{6}

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