When two progressive waves y1 = 4 sin (2x – 6t) andy2 = 3 sin are superimposed, the amplitude of the resultant wave is

Engineering

Physics

Reflection Refraction and Superposition of Wave

Question

When two progressive waves y₁ = 4 sin (2x – 6t) and

y₂ = 3 sin $(2 x - 6 t - \frac{π}{2})$

are superimposed, the amplitude of the resultant wave is

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$A = \sqrt{A_{1}^{2} + A_{2}^{2} + 2 A_{1} A_{2} cosθ}$

A₁ = 4

A₂ = 3 $\Rightarrow$ A = 5

$ϕ$ = – $π$ /2