Alkenes react with HBr via electrophilic addition following Markovnikov's rule (H adds to less substituted carbon). With HBr/H₂O₂, anti-Markovnikov addition occurs via a radical mechanism. The alkene that gives the same major product in both cases must be symmetric, so the addition of H and Br is identical regardless of the mechanism. Only symmetric alkenes like 2-butene (option 2) yield the same product (2-bromobutane).

Final Answer: Option 2