Which of the following facts about the complex [Cr(NH3)6] Cl3 is wrong ?
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In case of d3 configuration, the number of unpaired electrons remains 3 whether the ligand is strong field or weak field. The hybridisation scheme can be shown as follow :

Hence the complex is inner orbital complex as it involves (n – 1) d orbitals for hybridisation, ; so n = 3 (here n is number of unpaired electron(s)).