Chloroform (CHCl₃) is produced by the haloform reaction, where a methyl ketone (or compound oxidized to one) reacts with hypochlorite. Among the options:

Heating 3-pentanone (a ketone without a methyl group) with bleaching powder (source of hypochlorite) will not yield chloroform, as it cannot undergo the haloform reaction.

The correct process is boiling trichloroacetic acid (CCl₃COOH) with dilute NaOH. The base hydrolyzes it to sodium trichloroacetate, which decarboxylates to yield chloroform: $\mathrm{CCl}{}_3\mathrm{COOH}+\mathrm{NaOH}\to \mathrm{CCl}{}_3\mathrm{COONa}+H_{2}O$, followed by $\mathrm{CCl}{}_3\mathrm{COONa}\to \mathrm{CHCl}{}_3+\mathrm{NaHCO}{}_3$.

Final Answer: Boiling trichloroacetic acid with dilute sodium hydroxide