Engineering
Chemistry
Free radical
Alkane
Question

Which statement is incorrect for Kolbe's electrolysis.

During Kolbe's electrolysis reduction reaction take place at cathode.

pOH of electrolytic solution increases during reaction.

CO2 gas liberates at anode.

When salt of maleic acid is used then ethyne will be major product.

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Solution

Kolbe's electrolysis involves electrolysis of concentrated sodium/potassium salts of carboxylic acids. At anode, decarboxylation occurs producing alkane (for monocarboxylic acids) and CO2. At cathode, H2 gas evolves via reduction of H2O, increasing OH- concentration and thus pOH. For maleic acid (HOOC-CH=CH-COOH), electrolysis gives acetylene (ethyne) as major product. All statements are correct except: "When salt of maleic acid is used then ethyne will be major product" is incorrect - maleic acid electrolysis actually yields acetylenedicarboxylic acid, not ethyne.

Final answer: "When salt of maleic acid is used then ethyne will be major product" is the incorrect statement.