This question involves identifying the product (X) formed from the ozonolysis of a given alkene. Ozonolysis is a reaction where an alkene is cleaved by ozone (O₃) to form carbonyl compounds (aldehydes or ketones). The carbon-carbon double bond is broken, and oxygen atoms are added to each carbon, resulting in carbonyl groups.

The given reactant is an alkene with the structure: $C H_{3} - C H = C H - C H_{3}$ (2-butene).

Step 1: Ozonolysis cleaves the double bond. The carbon atoms that were part of the double bond become carbonyl carbons.

Step 2: For each carbon in the double bond, determine the carbonyl product:

The left carbon (CH₃-CH=) becomes an aldehyde: CH₃CHO (acetaldehyde).
The right carbon (=CH-CH₃) also becomes an aldehyde: CH₃CHO (acetaldehyde).

So, the products are two molecules of acetaldehyde.

Step 3: Compare with the options. The correct structure for acetaldehyde is: $C H_{3} - C (= O) - H$ , which matches the first option.

Final Answer: The product (X) is acetaldehyde, represented by the first option.

Related Topics

Ozonolysis: A specific oxidative cleavage reaction where alkenes react with ozone to form carbonyl compounds. It is used to determine the position of double bonds in alkenes. The general rule is that each carbon of the double bond becomes a carbonyl carbon, with aldehydes formed if the carbon is terminal and ketones if it is internal.

Formulae

The reaction can be generalized as: $R 1 R 2 C = C R 3 R 4 \to R 1 R 2 C = O + O = C R 3 R 4$ after reductive workup (e.g., with Zn/H₂O).